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1345.JumpGameIV.py
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'''
Given an array of integers arr, you are initially
positioned at the first index of the array.
In one step you can jump from index i to index:
- i + 1 where: i + 1 < arr.length.
- i - 1 where: i - 1 >= 0.
- j where: arr[i] == arr[j] and i != j.
Return the minimum number of steps to reach the last
ndex of the array.
Notice that you can not jump outside of the array at
any time.
Example:
Input: arr = [100,-23,-23,404,100,23,23,23,3,404]
Output: 3
Explanation: You need three jumps from index
0 --> 4 --> 3 --> 9. Note that index 9 is
the last index of the array.
Example:
Input: arr = [7]
Output: 0
Explanation: Start index is the last index. You don't
need to jump.
Example:
Input: arr = [7,6,9,6,9,6,9,7]
Output: 1
Explanation: You can jump directly from index 0 to index
7 which is last index of the array.
Example:
Input: arr = [6,1,9]
Output: 2
Example:
Input: arr = [11,22,7,7,7,7,7,7,7,22,13]
Output: 3
Constraints:
- 1 <= arr.length <= 5 * 10^4
- -10^8 <= arr[i] <= 10^8
'''
#Difficulty: Hard
#28 / 28 test cases passed.
#Runtime: 1224 ms
#Memory Usage: 28.8 MB
#Runtime: 1224 ms, faster than 5.17% of Python3 online submissions for Jump Game IV.
#Memory Usage: 28.8 MB, less than 63.79% of Python3 online submissions for Jump Game IV.
class Solution:
def minJumps(self, arr: List[int]) -> int:
indices = {}
visited = set()
queue = [[0, 0]] # index, step
length = len(arr)
for ind, num in enumerate(arr):
if num not in indices:
indices[num] = []
indices[num].append(ind)
while queue:
index, steps = queue.pop(0)
if index == length - 1:
break
if indices[arr[index]]:
for i in indices[arr[index]]:
if i not in visited:
visited.add(i)
queue.append([i, steps+1])
indices[arr[index]] = []
if index - 1 > 0 and index - 1 not in visited:
visited.add(index-1)
queue.append([index-1, steps+1])
if index + 1 not in visited:
visited.add(index+1)
queue.append([index+1, steps+1])
return steps