find-duplicate-file-in-system.py

# Time:  O(n * l), l is the average length of file content
# Space: O(n * l)

# Given a list of directory info including directory path,
# and all the files with contents in this directory,
# you need to find out all the groups of duplicate files
# in the file system in terms of their paths.
#
# A group of duplicate files consists of at least two files that have exactly the same content.
#
# A single directory info string in the input list has the following format:
#
# "root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"
#
# It means there are n files (f1.txt, f2.txt ... fn.txt
# with content f1_content, f2_content ... fn_content, respectively) in
# directory root/d1/d2/.../dm. Note that n >= 1 and m >= 0. If m = 0, it means the directory is just the root directory.
#
# The output is a list of group of duplicate file paths. For each group,
# it contains all the file paths of the files that have the same content.
# A file path is a string that has the following format:
#
# "directory_path/file_name.txt"
#
# Example 1:
# Input:
# ["root/a 1.txt(abcd) 2.txt(efgh)", "root/c 3.txt(abcd)", "root/c/d 4.txt(efgh)", "root 4.txt(efgh)"]
# Output:
# [["root/a/2.txt","root/c/d/4.txt","root/4.txt"],["root/a/1.txt","root/c/3.txt"]]
# Note:
# No order is required for the final output.
# You may assume the directory name, file name and file content only has letters
# and digits, and the length of file content is in the range of [1,50].
#
# The number of files given is in the range of [1,20000].
# You may assume no files or directories share the same name in the same directory.
# You may assume each given directory info represents a unique directory.
# Directory path and file info are separated by a single blank space.
#
# Follow-up beyond contest:
# 1. Imagine you are given a real file system, how will you search files? DFS or BFS?
# 2. If the file content is very large (GB level), how will you modify your solution?
# 3. If you can only read the file by 1kb each time, how will you modify your solution?
# 4. What is the time complexity of your modified solution?
#   What is the most time-consuming part and memory consuming part of it? How to optimize?
# 5. How to make sure the duplicated files you find are not false positive?

import collections


class Solution(object):
    def findDuplicate(self, paths):
        """
        :type paths: List[str]
        :rtype: List[List[str]]
        """
        files = collections.defaultdict(list)
        for path in paths:
           s = path.split(" ")
           for i in xrange(1,len(s)):
               file_name = s[0] + "/" + s[i][0:s[i].find("(")]
               file_content = s[i][s[i].find("(")+1:s[i].find(")")]
               files[file_content].append(file_name)

        result = []
        for file_content, file_names in files.iteritems():
            if len(file_names)>1:
                result.append(file_names)
        return result