forked from Garvit244/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
98.py
42 lines (36 loc) · 1.11 KB
/
98.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
'''
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
'''
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def isValidBST(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if not root:
return True
stack, result = [], []
while stack or root:
if root:
stack.append(root)
root = root.left
else:
root = stack.pop()
result.append(root.val)
root = root.right
previous = result[0]
for index in range(1, len(result)):
if previous >= result[index]:
return False
previous = result[index]
return True