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Minimum Remove to Make Valid Parentheses.cpp
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Minimum Remove to Make Valid Parentheses.cpp
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/*
Solution by Rahul Surana
***********************************************************
Given a string s of '(' , ')' and lowercase English characters.
Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions )
so that the resulting parentheses string is valid and return any valid string.
Formally, a parentheses string is valid if and only if:
It is the empty string, contains only lowercase characters, or
It can be written as AB (A concatenated with B), where A and B are valid strings, or
It can be written as (A), where A is a valid string.
***********************************************************
*/
#include <bits/stdc++.h>
class Solution {
public:
// string df(int i, string s,string a){
// if(i>=s.length()) return a;
// if(s[i] == '('){
// string f = df(i+1,s,"(");
// }
// else if(s[i] == ')') return a;
// else{
// a += s[i] + df(i+1,s,"");
// }
// return "";
// }
string minRemoveToMakeValid(string s) {
int cb = 0;
string ans;
for(int i = 0; i < s.length(); i++){
if(s[i] == ')'){
if(cb==0) s[i] = '#';
else cb--;
}
else if(s[i] == '('){
cb++;
}
}
cb = 0;
for(int i = s.length()-1; i >=0 ; i--){
if(s[i] == '('){
if(cb==0) s[i] = '#';
else cb--;
}
else if(s[i] == ')'){
cb++;
}
}
for(int i = 0; i < s.length(); i++){
if(s[i] != '#'){
ans+=s[i];
}
}
return ans;
}
};