Doubt about BeamDyn. #1435
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Hello to all, I've a doubt about two outputs of BeamDyn. Is this velocity what is the difference between node and sectional? Thanks in advance |
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Replies: 4 comments 4 replies
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Dear @aitorplaza, It sounds like you are referring to BeamDyn's nodal outputs, in which case I agree that Best regards, |
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Dear @jjonkman, Chord [m],Twist [deg],Thickness [%],Neutral axis x [m],Neutral axis y [m],Neutral axis local x [%],Neutral axis local y [%],User axis x [%],User axis y [%],Centre of mass x [%],Centre of mass y [%],Mass axis orientation [deg],Mass/unit length [kg/m],Polar inertia/unit length [kgm],Radii of gyration ratio [-],Principal axis orientation [deg],Shear centre x [%],Shear centre y [%],Bending stiffness about xp [Nm²],Bending stiffness about yp [Nm²],Torsional stiffness [Nm²],Axial stiffness [N] My questions are: Any references, workflows, or example implementations would be greatly appreciated. |
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Dear @jjonkman, for the first question I meant why are the edgewise and flapwise shear stiffness(KshrFlp, KshrEdg) values usually not given explicitly in blade data? can assume? Best regards, |
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Dear @jjonkman, I have a few questions regarding BeamDyn:
For BeamDyn.blade, is it correct to compute both the mass and stiffness matrices about point O (xo, yo, zo)? Should these properties always be calculated about the same point as (kp_xr, kp_yr, kp_zr), or is it acceptable to choose a different reference point? As an example, consider the first section of the blade at the root, which is cylindrical. If O is located as shown in the figure below: Here, XC is small and YC is relatively large (about 50% of the chord). This leads to the following in the stiffness matrix: K44 = Hxx + EA·YC² K55 = Hyy + EA·XC² Because XC and YC differ significantly, K44 and K55 also differ, even though for a cylinder I would expect them to be nearly equal. In my blade data, the bending stiffness about xp is almost equal to that about yp, meaning Hxx ≈ Hyy. Could you clarify why this discrepancy arises? Best regards, |
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Dear @aitorplaza,
It sounds like you are referring to BeamDyn's nodal outputs, in which case I agree that
TVxgis the time-derivative ofAbsXg. In BeamDyn, nodes are located at a given blade cross section, so the terms "node" and "section" in the BeamDyn documentation can be viewed as interchangeable.Best regards,