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Theorem: CBC Casper needs at least 3 rounds to have n/3 fault tolerance #16

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nrryuya opened this issue Sep 12, 2019 · 1 comment
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nrryuya commented Sep 12, 2019

Also, explain this is not because of the whole CBC but "no in-protocol threshold" philosophy, or strictly speaking, "decoupling of safety/liveness threshold"

@nrryuya nrryuya mentioned this issue Sep 12, 2019
@nrryuya nrryuya self-assigned this Sep 13, 2019
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nrryuya commented Oct 1, 2019

Move to #32

@nrryuya nrryuya closed this as completed Oct 1, 2019
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