markdown.md

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[Toc]

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`code

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==highlight==

power^2^

• unorder

  • list
  1. first
  2. second

• todo

• list

#include <iostream>
#include <sstream>
#include <utility>
#include <vector>
#include <tuple>
#include <bitset>
#include <regex>
std::vector<int> a;
int main()
{
	std::regex rx("\\w*\\.(cpp|cc|cxx)", std::regex::icase);
	std::smatch results;
	std::string test_str("dsagdas23123.cpp\n32123.Cpp\n423cdf.Cc\n	dasd.txt\n213asdf\nasd.ad");
	/*if (std::regex_search(test_str, results, rx))
		std::cout << results.str();*/
	for (std::sregex_iterator it(test_str.begin(), test_str.end(), rx), end;
		it != end; ++it)
		std::cout << it->str() << std::endl;
}

$$ LaTeX $$

Monday	Tuesday	Wednesday	Thursday	Friday

Quote(仅限标题跳转) ——Name¹

bilibili

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$$ \mathop \Phi \nolimits_e = \oint { \mathord{ \buildrel{ \lower3pt \hbox{$ \scriptscriptstyle \rightharpoonup$}} \over E} \cdot {d \mathord{ \buildrel{ \lower3pt \hbox{$ \scriptscriptstyle \rightharpoonup$}} \over S}} = {1 \over {{\varepsilon _0}}}\sum {q} } $$

$\alpha$

$$ x_i,{\rm x_i} \text{ a b} $$

pie
	title 这是一个饼
	"绿豆饼" :12
	"红豆饼" :88
	"黑豆饼" :144
	

Loading

graph LR
A
0(B)
1((C))
2{{D}}
3[[E]]
4[(F)]
0-->1--Text-->0-.->|Lext|2
3===4---1

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flowchart LR
0(B\nB)
1((C))
2{{D}}
3[[E]]
4[(F)]
0 o--------o 1
0 <---> 2
2 x--x 3
4-->1

Loading

<iframe src="//player.bilibili.com/player.html?aid=31289365&bvid=BV1iW411d7hd&cid=54672422&page=1" scrolling="no" border="0" frameborder="no" framespacing="0" allowfullscreen="true"> </iframe>

Footnotes

1. from this ↩