fizzBuzz.py

"""
Given an integer n, return a string array answer (1-indexed) where:

answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
answer[i] == "Fizz" if i is divisible by 3.
answer[i] == "Buzz" if i is divisible by 5.
answer[i] == i (as a string) if none of the above conditions are true.


Example 1:
Input: n = 3
Output: ["1","2","Fizz"]

Runtime: 36 ms, faster than 99.03% of Python3 online submissions for Fizz Buzz.
Memory Usage: 15 MB, less than 88.12% of Python3 online submissions for Fizz Buzz.
"""


class Solution:
    def fizzBuzz(self, n: int) -> list[str]:
        output = []
        for i in range(1, n+1):
            if i % 3 == 0 and i % 5 == 0:
                output.append("FizzBuzz")
            elif i % 3 == 0:
                output.append("Fizz")
            elif i % 5 == 0:
                output.append("Buzz")
            else:
                output.append(str(i))
        return output