31. 下一个排列.ipynb

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      "[1, 2, 3, 4]\n"
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   "source": [
    "class Solution:\n",
    "    def nextPermutation(self, nums: [int]) -> None:\n",
    "        \"\"\"\n",
    "        Do not return anything, modify nums in-place instead.\n",
    "        \"\"\"\n",
    "        flag = False\n",
    "        for i in range(len(nums)-2,-1,-1):\n",
    "            if nums[i+1] > nums[i]:\n",
    "                temp = i\n",
    "                for j in range(i+1,len(nums)):\n",
    "                    if nums[j] > nums[i]:\n",
    "                        temp = j\n",
    "                    else:\n",
    "                        break\n",
    "                number = nums[i]\n",
    "                nums[i] = nums[temp]\n",
    "                nums[temp] = number\n",
    "                nums[i+1:] = sorted(nums[i+1:])\n",
    "                flag = True\n",
    "                break\n",
    "        if not flag:\n",
    "            nums.sort()\n",
    "        print(nums)\n",
    "    \n",
    "s = Solution()\n",
    "s.nextPermutation([4,3,2,1])"
   ]
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