Time: 34 ms (74.62%), Space: 16.8 MB (17.17%) - LeetHub

Author: Deepak5113

0151-reverse-words-in-a-string/0151-reverse-words-in-a-string.py

@@ -0,0 +1,15 @@
+class Solution:
+    def reverseWords(self, s: str) -> str:
+        # Step 1: Trim the string to remove leading and trailing spaces
+        s = s.strip()
+        
+        # Step 2: Split the string into words based on spaces
+        words = s.split()
+        
+        # Step 3: Reverse the list of words
+        words.reverse()
+        
+        # Step 4: Join the reversed list of words with a single space between them
+        reversed_string = ' '.join(words)
+        
+        return reversed_string