|
| 1 | +""" |
| 2 | +[Problem] |
| 3 | +https://leetcode.com/problems/combination-sum/ |
| 4 | +
|
| 5 | +candidates: unique array of integers |
| 6 | +return a list of all unique combinations of candidates == target |
| 7 | +any order |
| 8 | +
|
| 9 | +하나의 숫자는 candidates에서 무제한으로 선택할 수 있다. |
| 10 | +두 조합이 서로 다르다고 간주되는 조건은, 선택된 숫자 중 적어도 하나의 개수가 다를 때이다. |
| 11 | +[Brainstorming] |
| 12 | +DFS를 이용해서 Combination을 만든다. |
| 13 | +종료조건: target == sum || target > sum |
| 14 | +
|
| 15 | +[Plan] |
| 16 | +1. candidates를 오름차순 정렬 |
| 17 | +2. DFS |
| 18 | +
|
| 19 | +[Complexity] |
| 20 | +N -> candidates.length |
| 21 | +M -> approximately target divided by the smallest candidate. -> target / min(candidates) |
| 22 | +Time: O(N^M) |
| 23 | +Space: O(N + M) |
| 24 | + - 재귀 호출 스택: 깊이는 최대 target / min(candidates) |
| 25 | + - chosen: 재귀 스택 깊이 만큼 공간 차지 |
| 26 | + - cache: 최악의 경우 answer와 같은 개수의 조합 저장 -> O(number of combinations) |
| 27 | +""" |
| 28 | + |
| 29 | +from typing import List |
| 30 | + |
| 31 | + |
| 32 | +class Solution: |
| 33 | + def combinationSum1(self, candidates: List[int], target: int) -> List[List[int]]: |
| 34 | + cache = set() |
| 35 | + answer = [] |
| 36 | + chosen = [] |
| 37 | + |
| 38 | + def dfs(sum: int) -> None: |
| 39 | + nonlocal target, candidates, cache, answer, chosen |
| 40 | + print(chosen) |
| 41 | + if sum > target: |
| 42 | + return |
| 43 | + if sum == target: |
| 44 | + copied_chosen = chosen[:] |
| 45 | + copied_chosen.sort() |
| 46 | + |
| 47 | + cache_key = tuple(copied_chosen) |
| 48 | + if cache_key in cache: |
| 49 | + # print(f"already exists {cache_key} in cache") |
| 50 | + return |
| 51 | + cache.add(cache_key) |
| 52 | + answer.append(copied_chosen) |
| 53 | + |
| 54 | + for candidate in candidates: |
| 55 | + chosen.append(candidate) |
| 56 | + dfs(sum + candidate) |
| 57 | + chosen.pop() |
| 58 | + |
| 59 | + dfs(0) |
| 60 | + return answer |
| 61 | + |
| 62 | + """ |
| 63 | + 중복 조합 방지 another solution |
| 64 | + ref: https://www.algodale.com/problems/combination-sum/ |
| 65 | +
|
| 66 | + [Complexity] |
| 67 | + N -> candidates.length |
| 68 | + M -> target / min(candidates) |
| 69 | + Time: O(N^M) |
| 70 | + Space: O(M) |
| 71 | + """ |
| 72 | + |
| 73 | + def combinationSum(self, candidates: List[int], target: int) -> List[List[int]]: |
| 74 | + answer = [] |
| 75 | + combi = [] |
| 76 | + |
| 77 | + def dfs(sum: int, start: int) -> None: |
| 78 | + nonlocal target, answer, combi, candidates |
| 79 | + |
| 80 | + if sum > target: |
| 81 | + return |
| 82 | + if sum == target: |
| 83 | + answer.append(combi[:]) |
| 84 | + return |
| 85 | + |
| 86 | + for index in range(start, len(candidates)): |
| 87 | + candidate = candidates[index] |
| 88 | + combi.append(candidate) |
| 89 | + dfs(sum + candidate, index) |
| 90 | + combi.pop() |
| 91 | + |
| 92 | + dfs(0, 0) |
| 93 | + return answer |
| 94 | + |
| 95 | + |
| 96 | +sol = Solution() |
| 97 | +# print(sol.combinationSum([2,3,6,7], 7)) |
| 98 | +print(sol.combinationSum([2, 3, 5], 8)) |
| 99 | +# print(sol.combinationSum([2], 1)) |
| 100 | + |
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