Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

LeetCode 206. 反转链表 #63

Open
Chocolate1999 opened this issue Oct 4, 2020 · 0 comments
Open

LeetCode 206. 反转链表 #63

Chocolate1999 opened this issue Oct 4, 2020 · 0 comments
Labels
链表 数据结构-链表

Comments

@Chocolate1999
Copy link
Owner

仰望星空的人,不应该被嘲笑

题目描述

反转一个单链表。

示例:

输入: 1->2->3->4->5->NULL
输出: 5->4->3->2->1->NULL

进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/reverse-linked-list
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

解题思路

非递归解法

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
/**
 * @param {ListNode} head
 * @return {ListNode}
 */
var reverseList = function(head) {
    let pre = null;
    let cur = head;
    while(cur){
        let tmp = cur.next;
        cur.next = pre;
        pre = cur;
        cur = tmp;
    }
    return pre;
};

递归解法

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
/**
 * @param {ListNode} head
 * @return {ListNode}
 */
var reverseList = function (head) {
    let reverse = (pre, cur) => {
        if (!cur) return pre;
        let tmp = cur.next;
        cur.next = pre;
        return reverse(cur, tmp);
    }
    return reverse(null, head);
};

最后

文章产出不易,还望各位小伙伴们支持一波!

往期精选:

小狮子前端の笔记仓库

leetcode-javascript:LeetCode 力扣的 JavaScript 解题仓库,前端刷题路线(思维导图)

小伙伴们可以在Issues中提交自己的解题代码,🤝 欢迎Contributing,可打卡刷题,Give a ⭐️ if this project helped you!

访问超逸の博客,方便小伙伴阅读玩耍~

学如逆水行舟,不进则退
@Chocolate1999 Chocolate1999 added the 链表 数据结构-链表 label Oct 4, 2020
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
链表 数据结构-链表
Projects
None yet
Development

No branches or pull requests

1 participant