-
Notifications
You must be signed in to change notification settings - Fork 0
/
1448. Count Good Nodes in Binary Tree.js
66 lines (49 loc) · 1.53 KB
/
1448. Count Good Nodes in Binary Tree.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
/*
Given a binary tree root, a node X in the tree is named good if in the path from root to X there are no nodes with a value greater than X.
Return the number of good nodes in the binary tree.
Example 1:
Input: root = [3,1,4,3,null,1,5]
Output: 4
Explanation: Nodes in blue are good.
Root Node (3) is always a good node.
Node 4 -> (3,4) is the maximum value in the path starting from the root.
Node 5 -> (3,4,5) is the maximum value in the path
Node 3 -> (3,1,3) is the maximum value in the path.
Example 2:
Input: root = [3,3,null,4,2]
Output: 3
Explanation: Node 2 -> (3, 3, 2) is not good, because "3" is higher than it.
Example 3:
Input: root = [1]
Output: 1
Explanation: Root is considered as good.
Constraints:
The number of nodes in the binary tree is in the range [1, 10^5].
Each node's value is between [-10^4, 10^4].
*/
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var goodNodes = function(root) {
let goodNodesCount = 0;
let walkTree = (node, pathMax = -1 * 2 ** 31) => {
if (!node) { return; }
walkTree(node.left, node.val > pathMax ? node.val : pathMax);
walkTree(node.right, node.val > pathMax ? node.val : pathMax);
//console.log(pathMax, node.val);
if (pathMax <= node.val) {
goodNodesCount++;
}
};
walkTree(root);
return goodNodesCount;
};