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104.maximum-depth-of-binary-tree.cpp
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/*
* @lc app=leetcode id=104 lang=cpp
*
* [104] Maximum Depth of Binary Tree
*
* https://leetcode.com/problems/maximum-depth-of-binary-tree/description/
*
* algorithms
* Easy (67.63%)
* Likes: 3634
* Dislikes: 93
* Total Accepted: 1.1M
* Total Submissions: 1.6M
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* Given the root of a binary tree, return its maximum depth.
*
* A binary tree's maximum depth is the number of nodes along the longest path
* from the root node down to the farthest leaf node.
*
*
* Example 1:
*
*
* Input: root = [3,9,20,null,null,15,7]
* Output: 3
*
*
* Example 2:
*
*
* Input: root = [1,null,2]
* Output: 2
*
*
* Example 3:
*
*
* Input: root = []
* Output: 0
*
*
* Example 4:
*
*
* Input: root = [0]
* Output: 1
*
*
*
* Constraints:
*
*
* The number of nodes in the tree is in the range [0, 10^4].
* -100 <= Node.val <= 100
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int maxDepth1(TreeNode* root) {
if (root == nullptr)
return 0;
int leftDepth = maxDepth(root->left);
int rightDepth = maxDepth(root->right);
int depth = 1 + max(leftDepth, rightDepth);
return depth;
}
int maxDepth(TreeNode* root) {
if (root == nullptr)
return 0;
int depth = 0;
queue<TreeNode*> que;
que.push(root);
while (!que.empty()) {
int size = que.size();
for (int i = 0; i < size; ++i) {
TreeNode* node = que.front();
que.pop();
if (node->left)
que.push(node->left);
if (node->right)
que.push(node->right);
}
if (size)
++depth;
}
return depth;
}
};
// @lc code=end